34x^2+4x-1=0

Solution for 34x^2+4x-1=0 equation:

34x^2+4x-1=0

a = 34; b = 4; c = -1;
Δ = b2-4ac
Δ = 42-4·34·(-1)
Δ = 152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{152}=\sqrt{4*38}=\sqrt{4}*\sqrt{38}=2\sqrt{38}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{38}}{2*34}=\frac{-4-2\sqrt{38}}{68}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{38}}{2*34}=\frac{-4+2\sqrt{38}}{68}
$